Home » What Will Be The Maximum Speed Of A Car On A Road Turn Of Radius 30 M If The Coefficient Of Friction Between The Tyres And The Road Is 0.4 Take G 9.8M S² ? 10 Most Correct Answers

# What Will Be The Maximum Speed Of A Car On A Road Turn Of Radius 30 M If The Coefficient Of Friction Between The Tyres And The Road Is 0.4 Take G 9.8M S² ? 10 Most Correct Answers

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## What will be the maximum speed of a car on road turn of radius 30 m?

The maximum speed of a car on a road turn of radius 30m, if the coefficient of friction between the tyres and the road is 0.4, will be. A) 9.84 m/s.

## What is the maximum speed at which a car can round a curve?

If the mass of the car is m, the maximum friction force (which is the centripetal force) equals μ,FN or 0.80mg, this arises when the car is on the verge of skidding sideways. Therefore, the maximum speed is given by. mv2r=0.80mg or v=√0.80gr=√(0.80)(9.81 m/s2)(25 m)=14 m/s.

### What will be maximum speed of a car on a curved road of radius 30 m , If the coefficient of friction

What will be maximum speed of a car on a curved road of radius 30 m , If the coefficient of friction
What will be maximum speed of a car on a curved road of radius 30 m , If the coefficient of friction

## What will be the maximum speed of car on road?

In April 2018, the Union Ministry of Road Transport and Highways fixed the maximum speed limit on expressways at 120 km/h, for national highways at 100 km/h, and for urban roads at 70 km/h for M1 category of vehicles. The M1 category includes most passenger vehicles that have less than 8 seats.

## What will be the maximum speed of a car when it safely driven along a curved road of radius 100 m ?( G 10 m/s 2 μ 0.2 *?

The maximum speed of car which can be safely driven along a curve of radius 100 m is 14 m/s. So, the maximum speed of car is 14 m/s.

6 kmph.

## When a car takes a turn on a horizontal road the centripetal force is provided by the?

Horizontal force acting on the car is due to the friction. As said earlier a force acting on the center of turn, centripetal force is provided by the friction.

## How do you find the maximum speed of a banked curve?

The equation for the maximum velocity of a car on a banked curve is given as: v=√rg(tanθ−μs)1+μstanθ.

## See some more details on the topic What will be the maximum speed of a car on a road turn of radius 30 m if the coefficient of friction between the tyres and the road is 0.4 Take G 9.8m S² *? here:

### The maximum speed of a car on a road turn of radius class 11 …

The maximum speed of a car on a road turn of radius 30m, if the coefficient of friction between the tyres and the road is 0.4, will be. A) 9.84 m/s.

### The maximum speed of a car on a road turn of radius 30m, if …

The maximum speed of a car on a road turn of radius 30m, if the coefficient of friction between the tyres and the road is 0.4 ? g==9.8 m/s^2 …

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### Mechanics Practice Problem Set – Southington Public Schools

Answer: 2.1 m/s2 a. If the car is going to be towed onto the highway, it needs to reach a speed of 30 km/hr. How long will it take to get to …

### 6.3 Centripetal Force | University Physics Volume 1

What Coefficient of Friction Do Cars Need on a Flat Curve? … causing the car to turn in a circular path is due to friction between the tires and the road.

## What speed does a car need to have as it drives over a hill with radius 30 m in order to lose contact with the ground at the peak?

For the car to lose contact with the road, it must be traveling at a speed of 28 m/s or greater when it reaches the crest of the hill.

### A car is traveling at 50.0 km/h on a flat highway. (a) If the coefficient of friction between road a

A car is traveling at 50.0 km/h on a flat highway. (a) If the coefficient of friction between road a
A car is traveling at 50.0 km/h on a flat highway. (a) If the coefficient of friction between road a

## What is maximum speed physics?

Maximum speed is the highest rate of speed an athlete can attain. Acceleration refers to velocity, and because velocity has both a magnitude and direction associated with it, acceleration changes when athletes change the magnitude of their motion (how fast they are running), the direction of their motion, or both.

## What should be the coefficient of friction between the Tyres and the road when a car Travelling 60?

the coeffecient of friction between tyre and the road. = 0.71. HENCE THE COEFFICIENT OF FRICTION IS 0.71.

## What force is the centripetal force that keeps a car moving in a circular path?

As a car makes a turn, the force of friction acting upon the turned wheels of the car provides centripetal force required for circular motion.

## When a car takes a turn on a horizontal road the centripetal force is provided by the MCQ?

Correct option is (C) frictional force between the surface of the road and the tyres of the car.

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## When a car takes a circular level turn is it necessary centripetal?

Laws of Motion. What provides the centripetal force to a car taking turn on a level road? The centripetal force is provided by the force of friction between the tyres and road, to a car taking turn on a level road. Figure 5.16 shows the position-time graph of a particle of mass 4 kg.

## When a car is taking a circular turn on a banked road?

कार को किसी क्षैतिज सड़क पर वृत्तीय मोड़ लेने के लिए आवश्यक अभिकेंद्र त्वरण प्रदान करता है। Statement I: If a car is taking a turn on a banked road, then the normal contact force between car and road is greater than the weight of car (neglecting friction).

## What is the formula for maximum speed?

Also p=mv=γ(v)m0v. This leads to the equation F=˙p=m0ddtγ(v(t))v(t).

### Car on a banked curve

Car on a banked curve
Car on a banked curve

## What is the maximum speed formula?

The formula for speed is simply v(0)t. 19.8*15.9= 314.82 m/s for the maximum speed. Whatupdoc said: A spaceship ferrying workers to Moon Base I takes a straight-line path from the earth to the moon, a distance of 384,000 km.

## How do you calculate maximum?

If you are given the formula y = ax2 + bx + c, then you can find the maximum value using the formula max = c – (b2 / 4a). If you have the equation y = a(x-h)2 + k and the a term is negative, then the maximum value is k.

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