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What will be the equivalent resistance if three resistances of 2 4 and 6 ohm are connected in series?
Series Combination : Equivalent resistance Rs=R1+R2+R3=2+4+6=12Ω
What will be the equivalent resistance when resistance of 3 ohm 4 ohm and 6 ohm are connected 2 a in series B in parallel?
∴R=63+2+1=66=1ohm. Was this answer helpful?
Equivalent Resistance of Complex Circuits – Resistors In Series and Parallel Combinations
Images related to the topicEquivalent Resistance of Complex Circuits – Resistors In Series and Parallel Combinations
What is the total resistance if 2 resistance of 4 ohm and 6 ohm are connected in parallel?
Hence , Total resistance for series combination is 10Ω
How will you connect 2 ohm 3 ohm and 6 ohm resistors to get the equivalent resistance as?
Answer. Answer: Put 3 ohms in parallel with 6 ohms to produce an equivalent of 2 ohms by the parallel equivalent resistance rule [1/(1/3 + 1/6) = 2] Place that parallel combination in series with the other 2 ohms to get 4 ohms, since series resistances simply add [2+2=4].
What is the total resistance if 3 resistance of 4 ohms 6 ohms and 8 ohms respectively are connected in parallel?
Answer: Minimum resistance is obtained by connecting all three resistances in parallel => 1/R =1/4+1/6+1/8 =>1/R = 6/24+4/24+3/24 => 1/R = 13/24 => R =24/13 ohm . Hope it helps you.
How can three resistances of 2/3 and 6 Ohm be connected so as to give a total resistance of 1 ohm show the working of your solution?
Expert-verified answer
The resistors of 2ohm, 3ohm and 6ohm should be connected in parallel to have a total resistance of 1ohm. The three resistors of 2ohm, 3ohm and 6ohm should be connected parallel to have a total resistance of 1ohm.
How can three resistors of resistance 2 ohm 3 ohm and 6 ohm be connected to give a total resistance of a 4 ohm B 1 ohm?
To obtain a total resistance of 4 Ω from three resistors of given resistances, Firstly, connect the two resistors of 3Ω and 6Ω in parallel to get a total resistance of 2Ω which is less than the lowest individual resistance. Hence, the total resistance of the circuit is 4 Ω.
See some more details on the topic What will be the equivalent resistance if three resistance of 2 4 and 6 ohm are connected in series? here:
Resistors in Series and Parallel – University Physics Volume 2
The equivalent resistance of a set of resistors in a series connection is equal to the algebraic sum of the individual resistances. (a) Three resistors …
6.2 Resistors in Series and Parallel
. Since there is only one path for the charges to flow through, the current is the same through each resistor. The equivalent resistance of a set of resistors …
Electrical/Electronic – Series Circuits
“2. The total resistance of a series circuit is equal to the sum of individual resistances.” · RT = R1 + R2 + R3 · 2 + 2 + 3 = 7 Ohms · R total is 7 Ohms.
21.1 Resistors in Series and Parallel – College Physics
Figure 2. Three resistors connected in series to a battery (left) and the equivalent single or series resistance (right). To verify that resistances …
How will you connect three resistors of 2 ohm 3 ohm and 6 ohm to obtain?
Given three resistors of resistances 2 Ω, 3 Ω and 6 Ω. (a) A total resistance of 4 Ω can be obtained by connecting the 2 Ω resistance in series with the parallel combination of 3 Ω and 6 Ω. (b) We can obtain a total resistance of 1 Ω by connecting resistances of 2 Ω, 3 Ω and 6 Ω in parallel with each other.
When three resistors of resistances 3 Ohm 4 Ohm and 5 ohm are connected in parallel the current through them are in the ratio?
9:8:7.
How will you connect three resistors of 2 ohm 3 ohm and 5 ohm respectively?
Answer. The 2 ohm and 3 ohm resistors will be connected in series. This will give a resultant resistance of 5 ohm. Then this arrangement will be connected with the 5 ohm resistor in parallel.
How do you find the equivalent resistance between points A and B?
- R’ = 4 Ω + 4 Ω = 8 Ω
- Now the resistances R’, R3 and R4 are in parallel so the equivalent resistance of the circuit would be.
- Therefore the equivalent resistance between the two points A and B in the given circuit is 1.85 Ω.
Two resistors connected in series have an equivalent resistance of 690 Ω. When they are connected in
Images related to the topicTwo resistors connected in series have an equivalent resistance of 690 Ω. When they are connected in
When a 4 Ω resistor is connected across the terminals of a 2 V battery the number of coulombs passing through the resistor per second is * 2 points?
Therefore 0.5 Coulombs passing through the resistor per second.
How can you combine three resistances each of 4 Ω such that the total resistance of the circuit is 6 Ω?
That is, for the two resistors in parallel the resistance is given as 41+41=0. 51=2ohms and this is added with the resistance of the third resistor in series as 2+4=6 ohms.
What is the minimum resistance which can be made using the following resistors 2 ohm 3 ohm and 5 ohm?
The minimum resistance which can be made using five resistors is 0.04 ohms. Explanation: In parallel combination of resistors, the equivalent resistance is minimum.
How should the two resistances of 2 ohms each be Connencted so as to produce an equivalent resistance of 1 ohm?
The two resistors of 2 Ω each should be connected in parallel combination to produce equivalent resistance of 1 Ω.
What is the total resistance of two resistance of 4 ohm and 6 ohm and 8 ohms respectively are connected in parallel?
The combined resistance of the system in parallel is 2.67 ohms.
How will you join three resistors of resistance 4 W 6 W and 12 W to get an equivalent resistance of 8 W?
⇒ 1/R(parallel) = 1/R2 + 1/R3. ⇒ R(parallel) = 4 Ω. Now, the Resistor R1 = 4Ω is connected in series with the equivalent resistance of 12 Ω and 6 Ω in parallel. Hence to get the equivalent resistance of 8 Ω we can connect 12 Ω and 6 Ω in parallel and then connect 4 Ω in series.
What is the total resistance if three resistance of 3 ohm are connected in series?
Solving R1 = 3 ohms. If we connect all three Resistances, in series, 3+3+3 = 9 ohms.
How many 176 Ω resistors in parallel are required to carry 5 a on a 220 V line?
Therefore, four resistors of 176 Ω are required to draw the given amount of current.
What is the resistance between and B?
RAB=28=4Ω
What is the highest and lowest resistance which can be obtained by combining?
(a) To get the highest resistance, all the resistors must be connected in series. Therefore, the highest resistance is 48 Ω. (b) To get the lowest resistance, all the resistors must be connected in parallel. Therefore, the lowest resistance of the arrangement is 2 Ω.
Three resistors 1 ohm , 2 ohm, and 3 ohm are connected in series, what is the total resistance of
Images related to the topicThree resistors 1 ohm , 2 ohm, and 3 ohm are connected in series, what is the total resistance of
What is a the highest B the lowest total resistance that can be secured by combination of four?
Solution : ( a )The highest resistance can be secured (or obtained) by connecting all the four coils in series. In this case, <br> `R_s + R_1 + R_2 +R_3 +R_4` <br> ` = 4 + 8 + 12 +24 =48 Omega` <br> Thus, the highest resistance which can be secured is `48 Omega`.
What is the highest and lowest resistance?
Expert-verified answer
(a) The highest resistance is when the resistances are connected in series. Hence, the highest resistance is 48 Ω. Hence, the lowest resistance is 2 Ω.
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