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=2+3+4=9ΩAnswer: Two in parallel one in series. And next we add the third resistor in series, when in series resistors are simply added, therefore: 1 ohm (obtained earlier) + 2 ohm (third resistor) = 3 ohm !∴R=63+2+1=66=1ohm. Was this answer helpful?
How will you combine three 2 ohm resistor to have an equivalent resistance of 3 ohm?
Answer: Two in parallel one in series. And next we add the third resistor in series, when in series resistors are simply added, therefore: 1 ohm (obtained earlier) + 2 ohm (third resistor) = 3 ohm !
What is the total resistance of 3 ohms and 2 ohms resistors that are connected in parallel?
∴R=63+2+1=66=1ohm. Was this answer helpful?
How can three resistors of resistances 2 Ω, 3 Ω, and 6 Ω be connected to give a total resistance of
Images related to the topicHow can three resistors of resistances 2 Ω, 3 Ω, and 6 Ω be connected to give a total resistance of
What is the equivalent resistance of 2 and 4 ohm if they are connected in series *?
Series Combination : Equivalent resistance Rs=R1+R2+R3=2+4+6=12Ω
How can three resistors of resistance 2 ohm 3 ohm and 4 ohm?
How can three resistors of resistances 2 , 3 , and 6 be connected to give a total resistance of (a) 4 , (b) 1 ? Answer : (i) We can get a total resistance of 4 by connecting the 2 resistance in series with the parallel combination of 3 and 6 .
How can three resistors of resistances 2 Ω 3 Ω and 6ω be connected to give a total resistance of a 4 Ω B 1 Ω?
To obtain a total resistance of 4 Ω from three resistors of given resistances, Firstly, connect the two resistors of 3Ω and 6Ω in parallel to get a total resistance of 2Ω which is less than the lowest individual resistance. Hence, the total resistance of the circuit is 4 Ω.
How can three resistors of resistance 2 ohm 3 ohm and 6 ohm be connected to give a total resistance a 4 ohm B 1 ohm?
Given three resistors of resistances 2 Ω, 3 Ω and 6 Ω. (a) A total resistance of 4 Ω can be obtained by connecting the 2 Ω resistance in series with the parallel combination of 3 Ω and 6 Ω.
What is the resultant resistance when 2 ohm 3 ohm 6 ohm are connected in series?
Hence, the total resistance of the circuit is 4 Ω.
See some more details on the topic What Will Be The Equivalent Resistance If Three Resistors Of 2 Ohm 3 Ohm And 4 Ohm Are Connected In Series? here:
What is the equivalent resistance if three resistors of 2 ohm, 3 …
In Series R = R1 + R2 +R3 = 2 + 3 + 4 = 9 Ohms In Parallel 1/R = 1/R1 + 1/R2 + 1/R3 1/R = 1/2 +1/3 + 1//4 = 6 + 4 +3 / 12 = 13/12 R = 12/13 = 0.92.
Three resistors 2 ohm, 3 ohm and 4 ohm are connected so …
Three resistors 2 ohm, 3 ohm and 4 ohm are connected so that the equivalent resistance is 9 ohm The resistors are connected e all in series all in paralel.
6.2 Resistors in Series and Parallel
Figure 6.2.2 (a) Three resistors connected in series to a voltage source. … The potential drop across each resistor can be found using Ohm’s law.
PHYC 112 Question Set 12 Flashcards | Quizlet
Four 300-ohm resistors in series give an equivalent resistance of… 1200 ohms … Three resistors, 1-ohm, 2-ohm, and 3-ohm are connected in series.
When three resistors of resistances 3 Ohm 4 Ohm and 5 ohm are connected in parallel the current through them are in the ratio?
9:8:7.
What is the formula of equivalent resistance?
The equivalent resistance of a 4-Ω and 12-Ω resistor placed in parallel can be determined using the usual formula for equivalent resistance of parallel branches: 1 / Req = 1 / R1 + 1 / R2 + 1 / R3 … Now the Ohm’s law equation (ΔV = I • R) can be used to determine the total current in the circuit.
What is the total resistance if two resistances of 4 ohms and 6 Ohms are connected in parallel?
Hence , Total resistance for series combination is 10Ω
How will you join three resistors of resistances 4 6and 12to get an equivalent Resistanceof 8?
⇒ 1/R(parallel) = 1/R2 + 1/R3. ⇒ R(parallel) = 4 Ω. Now, the Resistor R1 = 4Ω is connected in series with the equivalent resistance of 12 Ω and 6 Ω in parallel. Hence to get the equivalent resistance of 8 Ω we can connect 12 Ω and 6 Ω in parallel and then connect 4 Ω in series.
What is the total resistance if three resistance of 4 ohms 6 ohms and 8 ohms respectively are connected in parallel?
Answer: Minimum resistance is obtained by connecting all three resistances in parallel => 1/R =1/4+1/6+1/8 =>1/R = 6/24+4/24+3/24 => 1/R = 13/24 => R =24/13 ohm . Hope it helps you.
How can three resistors of resistance 2 ohm 3 ohm and 6 ohm be connected to give a total resistance
Images related to the topicHow can three resistors of resistance 2 ohm 3 ohm and 6 ohm be connected to give a total resistance
How will you connect three resistors of 2 ohm 3 ohm 5 ohm respectively so as to obtain a resultant resistance of 2.5 ohm draw the diagram to show arrangement?
To get the resistance of 2.5 Ώ, we will have to connect the resistors of values 2 Ώ and 3 Ώ in series, and this arrangement should be connected in parallel with the resistor of value 5 Ώ.
How can three resistances of 2/3 and 6 ohms be connected so as to give a total resistance of I Ohm justify your answer?
Expert-verified answer
The resistors of 2ohm, 3ohm and 6ohm should be connected in parallel to have a total resistance of 1ohm. The three resistors of 2ohm, 3ohm and 6ohm should be connected parallel to have a total resistance of 1ohm.
What is the minimum resistance which can be made using the following resistors 2 ohm 3 ohm and 5 ohm?
The minimum resistance which can be made using five resistors is 0.04 ohms. Explanation: In parallel combination of resistors, the equivalent resistance is minimum.
How can you combine three resistances each of 4 Ω such that the total resistance of the circuit is 6 Ω?
That is, for the two resistors in parallel the resistance is given as 41+41=0. 51=2ohms and this is added with the resistance of the third resistor in series as 2+4=6 ohms.
How many 176 Ω resistors in parallel are required to carry 5 a on a 220 V line?
Therefore, four resistors of 176 Ω are required to draw the given amount of current.
What is a the highest B the lowest total resistance that can be secured by combination of four?
Solution : ( a )The highest resistance can be secured (or obtained) by connecting all the four coils in series. In this case, <br> `R_s + R_1 + R_2 +R_3 +R_4` <br> ` = 4 + 8 + 12 +24 =48 Omega` <br> Thus, the highest resistance which can be secured is `48 Omega`.
How can three resistors of resistances 2ω 3 Ω and 6 Ω be connected to give a total resistance of a 1 Ω B 11 Ω?
<br> (b) To get a resistance of `1 Omega` from three given resistors of resistances `2 Omega,3 Omega,6 Omega`, we should connect all of them in parallel. The equivalent resistance is given by <br> `(1)/(R_p) = (1)/(2)+(1)/(3)+(1)/(6)= (3 + 2 + 1)/(6) = (6)/(6) = 1` i.e., `R_p = 1 Omega`.
Can you make a resistance 4.5 ohm Using these three draw the circuit?
Answer: Yes, by arranging the resistors of 2 ohm and 6 ohm in parallel and the resistor of 3 ohm in series.
What is the resistance between and B?
RAB=28=4Ω
When two resistance of 3 ohm and 6 ohm are connected in parallel then the equivalent resistance is?
Expert-verified answer
=2 OHM. HOPE IT HELPED U!
Physics: The equivalent resistance of three resistors A, B, and C connected in parallel is 1.714 ohm
Images related to the topicPhysics: The equivalent resistance of three resistors A, B, and C connected in parallel is 1.714 ohm
When the resistance of 5 ohm 15 ohm and 6 ohm connected parallel the equivalent resistance will be?
3.5is the right answer .
How do you find the equivalent resistance of three resistors?
Likewise, if three or more resistors each with the same value are connected in parallel, then the equivalent resistance will be equal to R/n where R is the value of the resistor and n is the number of individual resistances in the combination.
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